Electrostatics 7 Question 7
7. Two large vertical and parallel metal plates having a separation of $1 cm$ are connected to a DC voltage source of potential difference $X$. A proton is released at rest midway between the two plates. It is found to move at $45^{\circ}$ to the vertical just after release. Then $X$ is nearly
(2012)
(a) $1 \times 10^{-5} V$
(b) $1 \times 10^{-7} V$
(c) $1 \times 10^{-9} V$
(d) $1 \times 10^{-10} V$
Show Answer
Solution:
Net force is at $45^{\circ}$ from vertical.
$$ \begin{aligned} & \therefore \quad q E=m g \text { or } \frac{q X}{d}=m g \quad \because E=\frac{X}{d} \\ & \text { or } \\ & X=\frac{m g d}{q}=\frac{\left(1.67 \times 10^{-27}\right)(9.8)\left(10^{-2}\right)}{\left(1.6 \times 10^{-19}\right)} \\ & \approx 1 \times 10^{-9} V \end{aligned} $$
