Electrostatics 5 Question 9

10. A parallel plate capacitor with plates of area 1m2 each, are at a separation of 0.1m. If the electric field between the plates is 100N/C, the magnitude of charge on each plate is Take, ε0=8.85×1012C2Nm2

(a) 9.85×1010C

(Main 2019, 12 Jan II)

(b) 8.85×1010C

(c) 7.85×1010C

(d) 6.85×1010C

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Answer:

Correct Answer: 10. 0.198μA

Solution:

  1. If Q= charge on each plate, then

Q=CV=ε0AdEd=ε0AE

Here, A=1m2,E=100N/C

and

ε0=8.85×1012C2Nm2

So, by substituting given values, we get Q=8.85×1012×1×100=8.85×1010C



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