Electrostatics 5 Question 13
14. A parallel plate capacitor having capacitance is charged by a battery to a potential difference of between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is
(a)
(b)
(c)
(d)
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Solution:
- Energy stored in a charged capacitor is given by
Here,
After insertion of slab, capacitance will be
So, energy dissipated in the process will be equal to work done on the slab, i.e.