Electrostatics 5 Question 12

13. In the figure shown below, the charge on the left plate of the 10μF capacitor is 30μC. The charge on the right plate of the 6μF capacitor is

(Main 2019, 11 Jan I)

(a) +12μC

(b) +18μC

(c) 12μC

(d) 18μC

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Solution:

  1. Applying the concept of charge conservation on isolated plates of 10μF,6μF and 4μF. Since, 6μF and 4μF are in parallel, so total charge on this combination will be 30μC.

Charge on 6μF, capacitor

=C1C1+C2q=66+4×30=18μC

Since, the charge has been asked on the right plate of the capacitor. Thus, it would be +18μC.

Alternative method

Let charge on 6μF capacitor is qμC.

Now, V at 6μF=V at 4μF

q6μF=30q4μF(V=q/C)4q=6q+180q=18μC



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