SATHEE: Electrostatics 5 Question 11

Electrostatics 5 Question 11

12. In the figure shown, after the switch ’ $S$ ’ is turned from position ’ $A$ ’ to position ’ $B$ ‘, the energy dissipated in the circuit in terms of capacitance ’ $C$ ’ and total charge ’ $Q$ ’ is

(a) $\frac{3}{4} \cdot \frac{Q^{2}}{C}$

(b) $\frac{5}{8} \cdot \frac{Q^{2}}{C}$

(d) $\frac{3}{8} \cdot \frac{Q^{2}}{C}$

Show Answer

Answer:

Correct Answer: 12. $0.288 m J$ 13. $0.9 A$ 14. $V_{A B} = 25 V, V_{B C} = 75 V$

Solution:

In position ’ $A$ ’ of switch, we have a capacitor joined with battery.

So, energy stored in position

$U_{1} = \frac{1}{2} C ε^{2}$

When switch is turned to position $B$ , we have a charged capacitor joined to an uncharged capacitor.

Common potential in steady state will be

$V = \frac{total charge}{total capacity} = \frac{C ε}{4 C} = \frac{ε}{4}$

Now, energy stored will be

$\begin{aligned} U_{2} & = \frac{1}{2} (C_{e q}) {(V_{common})}^{2} \\ = \frac{1}{2} 4 C \times \frac{ε^{2}}{4} = \frac{1}{8} C ε^{2} \end{aligned}$

So, energy dissipated is

$\begin{aligned} Δ U & = U_{1} - U_{2} = \frac{1}{2} C ε^{2} - \frac{1}{8} C ε^{2} \\ = \frac{3}{8} C ε^{2} = \frac{3}{8} C {\frac{Q}{C}}^{2} = \frac{3}{8} \cdot \frac{Q^{2}}{C} \end{aligned}$

पिछला

अगला

Electrostatics 5 Question 11

12. In the figure shown, after the switch ’ $S$ ’ is turned from position ’ $A$ ’ to position ’ $B$ ‘, the energy dissipated in the circuit in terms of capacitance ’ $C$ ’ and total charge ’ $Q$ ’ is

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics 5 Question 11

12. In the figure shown, after the switch ’ S ’ is turned from position ’ A ’ to position ’ B ‘, the energy dissipated in the circuit in terms of capacitance ’ C ’ and total charge ’ Q ’ is

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

12. In the figure shown, after the switch ’ $S$ ’ is turned from position ’ $A$ ’ to position ’ $B$ ‘, the energy dissipated in the circuit in terms of capacitance ’ $C$ ’ and total charge ’ $Q$ ’ is