SATHEE: Electromagnetic Induction and Alternating Current 7 Question 3

Electromagnetic Induction and Alternating Current 7 Question 3

3. An arc lamp requires a direct current of $10 A$ at $80 V$ to function. If it is connected to a $220 V$ (rms), $50 H z A C$ supply, the series inductor needed for it to work is close to

(2016 Main)

(a) $80 H$

(b) $0.08 H$

(d) $0.065 H$

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Answer:

Correct Answer: 3. (d)

Solution:

Resultant voltage, $V^{2} = V_{R}^{2} + V_{L}^{2} \Rightarrow 220^{2} = 80^{2} + V_{L}^{2}$

Solving, we get

$\begin{aligned} V_{L} & \approx 205 V \\ X_{L} & = \frac{V_{L}}{I} = \frac{205}{10} = 20.5 Ω = ω L \\ ∴ L & = \frac{20.5}{2 π \times 50} = 0.065 H \end{aligned}$

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Electromagnetic Induction and Alternating Current 7 Question 3

3. An arc lamp requires a direct current of $10 A$ at $80 V$ to function. If it is connected to a $220 V$ (rms), $50 H z A C$ supply, the series inductor needed for it to work is close to

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electromagnetic Induction and Alternating Current 7 Question 3

3. An arc lamp requires a direct current of 10A at 80V to function. If it is connected to a 220V (rms), 50HzAC supply, the series inductor needed for it to work is close to

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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3. An arc lamp requires a direct current of $10 A$ at $80 V$ to function. If it is connected to a $220 V$ (rms), $50 H z A C$ supply, the series inductor needed for it to work is close to