Electromagnetic Induction and Alternating Current 7 Question 1

1. A solid metal cube of edge length 2cm is moving in a positive Y-direction at a constant speed of 6m/s. There is a uniform magnetic field of 0.1T in the positive Z-direction. The potential difference between the two faces of the cube perpendicular to the X-axis is

(Main 2019, 10 Jan I)

(a) 2mV

(b) 12mV

(c) 6mV

(d) 1mV

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Answer:

Correct Answer: 1. (b)

Solution:

  1. Potential difference between opposite faces of cube is

V= induced emf =Blv

where,

B= magnetic field =0.1T,

l= distance between opposite faces of cube

=2cm=2×102m and v= speed of cube =6ms1.

Hence, V=0.1×2×102×6=12mV



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