SATHEE: Electromagnetic Induction and Alternating Current 4 Question 13

Electromagnetic Induction and Alternating Current 4 Question 13

13. After the capacitor gets fully charged, $S_{1}$ is opened and $S_{2}$ is closed so that the inductor is connected in series with the capacitor. Then,

(2006, 6M)

(a) at $t = 0$ , energy stored in the circuit is purely in the form of magnetic energy.

(b) at any time $t > 0$ , current in the circuit is in the same direction.

(d) at any time $t > 0$ , maximum instantaneous current in the circuit may be $V \sqrt{\frac{C}{L}}$ .

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Answer:

Correct Answer: 13. (d)

Solution:

From conservation of energy,

$\begin{aligned} \frac{1}{2} L I_{max}^{2} & = \frac{1}{2} C V^{2} \\ I_{max} & = V \sqrt{\frac{C}{L}} \end{aligned}$

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Electromagnetic Induction and Alternating Current 4 Question 13

13. After the capacitor gets fully charged, S1 is opened and S2 is closed so that the inductor is connected in series with the capacitor. Then,

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13. After the capacitor gets fully charged, $S_{1}$ is opened and $S_{2}$ is closed so that the inductor is connected in series with the capacitor. Then,