Electromagnetic Induction and Alternating Current 4 Question 13
13. After the capacitor gets fully charged, $S _1$ is opened and $S _2$ is closed so that the inductor is connected in series with the capacitor. Then,
(2006, 6M)
(a) at $t=0$, energy stored in the circuit is purely in the form of magnetic energy.
(b) at any time $t>0$, current in the circuit is in the same direction.
(c) at $t>0$, there is no exchange of energy between the inductor and capacitor.
(d) at any time $t>0$, maximum instantaneous current in the circuit may be $V \sqrt{\frac{C}{L}}$.
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Answer:
Correct Answer: 13. (d)
Solution:
- From conservation of energy,
$$ \begin{array}{rlrl} & \frac{1}{2} L I _{\max }^{2} & =\frac{1}{2} C V^{2} \\ I _{\max } & =V \sqrt{\frac{C}{L}} \end{array} $$
