Electromagnetic Induction and Alternating Current 4 Question 10

####10. A coil of inductance 8.4mH and resistance 6Ω is connected to a 12V battery. The current in the coil is 1A at approximately the time

(1999,2M)

(a) 500s

(b) 20s

(c) 35ms

(d) 1ms

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Answer:

Correct Answer: 10. (d)

Solution:

  1. The current-time (it) equation in LR circuit is given by [Growth of current in LR circuit]

i=i0(1et/τL)

where,

i0=VR=126=2A

and

τL=LR=8.4×1036=1.4×103s

and

i=1A

t= ? 

(given)

Substituting these values in Eq. (i), we get

or

t=0.97×103st=0.97mst1ms



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