SATHEE: Electromagnetic Induction and Alternating Current 3 Question 6

Electromagnetic Induction and Alternating Current 3 Question 6

####7. A small square loop of wire of side $l$ is placed inside a large square loop of wire of side $L (L » l)$ . The loops are coplanar and their centres coincide. The mutual inductance of the system is proportional to

(1998, 2M)

(a) $l / L$

(b) $l^{2} / L$

(d) $L^{2} / l$

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Answer:

Correct Answer: 7. (b)

Solution:

Magnetic field produced by a current $i$ in a large square loop at its centre,

$B \propto \frac{i}{L} say B = K \frac{i}{L}$

$∴$ Magnetic flux linked with smaller loop,

$\begin{aligned} φ = B \cdot S \\ φ = K \frac{i}{L} (l^{2}) \end{aligned}$

Therefore, the mutual inductance

$M = \frac{φ}{i} = K \frac{l^{2}}{L} or M \propto \frac{l^{2}}{L}$

NOTE Dimensions of self inductance (L) or mutual inductance $(M)$ are [Mutual inductance] $=$ [ Self inductance]

$= [μ_{0}] [length]$

Similarly, dimensions of capacitance are

[capacitance $] = [ε_{0}]$ [length $]$

From this point of view, options (b) and (d) may be correct.

पिछला

अगला

Electromagnetic Induction and Alternating Current 3 Question 6

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electromagnetic Induction and Alternating Current 3 Question 6

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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