Electromagnetic Induction and Alternating Current 3 Question 2

2. Two coils P and Q are separated by some distance. When a current of 3 A flows through coil P, a magnetic flux of 103Wb passes through Q. No current is passed through Q. When no current passes through P and a current of 2 A passes through Q, the flux through P is

(a) 6.67×103Wb

(b) 6.67×104Wb

(c) 3.67×103Wb

(d) 3.67×104Wb

(Main 2019, 9 April II)

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Answer:

Correct Answer: 2. (b)

Solution:

  1. As, coefficient of mutual induction is same for both coils

Here,

NP=NQ=1,φPQ=?,φQP=103WbIQ=2A,IP=3A

Substituting values in Eq (i), we get

φPQ=IQφQPIP=23×103=0.667×103=6.67×104Wb



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