Electromagnetic Induction and Alternating Current 3 Question 1

####1. A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of 2.2kW. If the current in the secondary coil is 10A, then the input voltage and current in the primary coil are

(Main 2019, 10 April I)

(a) 440V and 5A

(b) 220V and 20A

(c) 220V and 10A

(d) 440V and 20A

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Answer:

Correct Answer: 1. (a)

Solution:

  1. Given, Number of turns in primary, N1=300

Number of turns in secondary, N2=150

Output power, P2=2.2kW=2.2×103W

Current in secondary coil, I2=10A

Output power, P2=I2 V2

V2=P2I2=2.2×10310=220V

We know that,

N1N2= Input voltage  Output voltage =V1V2V1=N1N2V2V1=300150×(220V) [using Eq. (i)] V1=440V Again, V1V2=I2I1I1=V2V1I2=220440×10I1=5A



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