Electromagnetic Induction and Alternating Current 2 Question 12
13. A square metal wire loop of side and resistance is moved with a constant velocity in a uniform magnetic field of induction as shown in the figure. The magnetic field lines are perpendicular to the plane of the loop (directed into the paper). The loop is connected to a network of resistors each of value .
What should be the speed of the loop so as to have a steady current of
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Answer:
Correct Answer: 13.
Solution:
- Given network forms a balanced Wheatstone’s bridge. The net resistance of the circuit is therefore
. Emf of the circuit is . Therefore, current in the circuit would be
Cross magnetic field passing through the loop is decreasing. Therefore, induced current will produce magnetic field in cross direction. Or direction of induced current is clockwise.