Current Electricity 5 Question 8

8. In a large building, there are 15 bulbs of 40W,5 bulbs of 100W,5 fans of 80W and 1 heater of 1kW. The voltage of the electric mains is 220V. The minimum capacity of the main fuse of the building will be

(2014 Main)

(a) 8A

(b) 10A

(c) 12A

(d) 14A

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Solution:

  1. Total power (P) consumed

=(15×40)+(5×100)+(5×80)+(1×1000)=2500W

As we know,

Power, P=VII=2500220A=12511=11.3A

Minimum capacity should be 12A.



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