Current Electricity 5 Question 2

2. The Wheatstone bridge shown in figure here, gets balanced when the carbon resistor is used as R1 has the color code (orange, red, brown). The resistors R2 and R4 are 80Ω and 40 Ω, respectively.

Assuming that the color code for the carbon resistors gives their accurate values, the color code for the carbon resistor is used as R3 would be

(2019 Main, 10 Jan II)

(a) brown, blue, black

(b) brown, blue, brown

(c) grey, black, brown

(d) red, green, brown

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Solution:

  1. The value of R1 (orange, red, brown)

=32×10=320Ω

Given, R2=80Ω and R4=40Ω

In balanced Wheatstone bridge condition,

R1R2=R3R4R3=R4×R1R2R3=40×32080 or R3=160Ω=16×101

Comparing the value of R3 with the colours assigned for the carbon resistor, we get

R3=16×101↗↑↑↑Brown Blue Brown 



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