SATHEE: Current Electricity 5 Question 14

Current Electricity 5 Question 14

14. A moving coil galvanometer has 50 turns and each turn has an area $2 \times 10^{- 4} m^{2}$ . The magnetic field produced by the magnet inside the galvanometer is $0.02 T$ . The torsional constant of the suspension wire is $10^{- 4} N - m r a d^{- 1}$ . When a current flows through the galvanometer, a full scale deflection occurs, if the coil rotates by $0.2 r a d$ . The resistance of the coil of the galvanometer is $50 Ω$ . This galvanometer is to be converted into an ammeter capable of measuring current in the range $0 - 1.0 A$ . For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance in ohms, is

Integer Answer Type Questions

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Solution:

Given, $N = 50, A = 2 \times 10^{- 4} m^{2}, C = 10^{- 4}, R = 50 Ω$ ,

$B = 0.02 T, θ = 0.2$

$rad N i_{g} A B = C θ$

$\begin{aligned} \Rightarrow i_{g} = \frac{C θ}{N A B} = \frac{10^{- 4} \times 0.2}{50 \times 2 \times 10^{- 4} \times 0.02} = 0.1 A \\ ∴ V_{a b} = i_{g} \times G = (i - i_{g}) S \Rightarrow 0.1 \times 50 = (1 - 0.1) \times S \end{aligned}$

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Current Electricity 5 Question 14

Integer Answer Type Questions

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

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अन्य संसाधन

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परीक्षा मंच

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Current Electricity 5 Question 14

Integer Answer Type Questions

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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