Current Electricity 4 Question 32

32. Two resistors, 400Ω and 800Ω are connected in series with a 6V battery. It is desired to measure the current in the circuit. An ammeter of 10Ω resistance is used for this purpose. What will be the reading in the ammeter? Similarly, if a voltmeter of 1000Ω resistance is used to measure the potential difference across the 400Ω resistor, what will be the reading in the voltmeter?

(1982,6M)

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Solution:

1000Ω (a)

(b)

Refer figure (a) Current through ammeter,

i= net emf  net resistance =6400+800+10=4.96×103A=4.96mA

Refer figure (b) Combined resistance of 1000Ω voltmeter and 400Ω resistance is,

R=1000×4001000+400=285.71Ωi=6(285.71+800)=5.53×103A

Reading of voltmeter

=Vab=iR=(5.53×103)(285.71)=1.58V



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