Current Electricity 4 Question 3

3. A galvanometer whose resistance is 50Ω, has 25 divisions in it. When a current of 4×104A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5V, it should be connected to a resistance of

(Main 2019, 12 Jan II)

(a) 250Ω

(b) 6200Ω

(c) 200Ω

(d) 6250Ω

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Solution:

  1. Current for deflection of pointer by

1 division =4×104A

So, current for full-scale deflection =Ig = Number of divisions × Current for 1 division Ig=25×4×104=1×102A

Now, let a resistance of R is put in series with galvanometer to make it a voltmeter of range 2.5V.

Then,

Ig(R+G)=VAB1×102(R+50)=2.5

[ Given, G=50Ω,VAB=2.5V]

R=25050=200Ω



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