Current Electricity 4 Question 16
16. A meter bridge is set-up as shown in figure, to determine an unknown resistance $X$ using a standard $10 \Omega$ resistor. The galvanometer shows null point when tapping-key is at $52 cm$ mark. The end-corrections are $1 cm$ and $2 cm$ respectively for the ends $A$ and $B$. The determined value of $X$ is
(2011)
(a) $10.2 \Omega$
(b) $10.6 \Omega$
(c) $10.8 \Omega$
(d) $11.1 \Omega$
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Solution:
- Using the concept of balanced Wheat stone bridge, we have,
$$ \begin{array}{rlrl} & \frac{P}{Q} & =\frac{R}{S} \\ \therefore & & \frac{X}{(52+1)} & =\frac{10}{(48+2)} \\ \therefore & X & =\frac{10 \times 53}{50}=10.6 \Omega \end{array} $$
$\therefore$ Correct option is (b).
