SATHEE: Current Electricity 4 Question 15

Current Electricity 4 Question 15

15. A heater is designed to operate with a power of $1000 W$ in a $100 V$ line. It is connected in combination with a resistance of $10 Ω$ and a resistance $R$ , to a $100 V$ mains as shown in the figure. What will be the value of $R$ so that the heater operates with a power of $62.5 W$ ?

(1978)

Show Answer

Solution:

For balanced meter bridge

$\begin{aligned} \frac{X}{R} & = \frac{l}{(100 - l)} (where, R = 90 Ω) \\ ∴ & \frac{X}{90} & = \frac{40}{100 - 40} \\ ∴ & X & = 60 Ω \end{aligned}$

$\begin{aligned} X & = R \frac{l}{(100 - l)} \\ \frac{Δ X}{X} & = \frac{Δ l}{l} + \frac{Δ l}{100 - l} = \frac{0.1}{40} + \frac{0.1}{60} \\ Δ X & = 0.25 \\ So, X & = (60 \pm 0.25) Ω \end{aligned}$

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Current Electricity 4 Question 15

15. A heater is designed to operate with a power of 1000W in a 100V line. It is connected in combination with a resistance of 10Ω and a resistance R, to a 100V mains as shown in the figure. What will be the value of R so that the heater operates with a power of 62.5W ?

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

15. A heater is designed to operate with a power of $1000 W$ in a $100 V$ line. It is connected in combination with a resistance of $10 Ω$ and a resistance $R$ , to a $100 V$ mains as shown in the figure. What will be the value of $R$ so that the heater operates with a power of $62.5 W$ ?