SATHEE: Current Electricity 4 Question 14

Current Electricity 4 Question 14

14. An electric bulb rated for $500 W$ at $100 V$ is used in a circuit having a $200 V$ supply. The resistance $R$ that must be put in series with the bulb, so that the bulb delivers $500 W$ is …… $Ω$ .

$(1987, 2 M)$

Analytical & Descriptive Question

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Solution:

In parallel, current distributes in inverse ratio of resistance. Hence,

$\frac{I - I_{g}}{I_{g}} = \frac{G}{S} \Rightarrow S = \frac{G I_{g}}{I - I_{g}}$

As $I_{g}$ is very small, hence

$\begin{aligned} S & = \frac{G I_{g}}{I} \\ b & = \frac{(100) (1 \times 10^{- 3})}{10} = 0.01 Ω \end{aligned}$

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Current Electricity 4 Question 14

14. An electric bulb rated for 500W at 100V is used in a circuit having a 200V supply. The resistance R that must be put in series with the bulb, so that the bulb delivers 500W is …… Ω.

Analytical & Descriptive Question

Solution:

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14. An electric bulb rated for $500 W$ at $100 V$ is used in a circuit having a $200 V$ supply. The resistance $R$ that must be put in series with the bulb, so that the bulb delivers $500 W$ is …… $Ω$ .