SATHEE: Current Electricity 2 Question 9

Current Electricity 2 Question 9

9. In the given circuit, the internal resistance of the $18 V$ cell is negligible. If $R_{1} = 400 Ω, R_{3} = 100 Ω$ and $R_{4} = 500 Ω$ and the reading of an ideal voltmeter across $R_{4}$ is $5 V$ , then the value of $R_{2}$ will be

(2019 Main, 9 Jan II)

(a) $550 Ω$

(b) $230 Ω$

(d) $450 Ω$

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Solution:

According to question, the voltage across $R_{4}$ is 5 volt, then the current across it

According to Ohm’s law,

$\begin{matrix} \Rightarrow V = I R \Rightarrow 5 = I_{1} \times R_{4} \\ \Rightarrow 5 = I_{1} \times 500 \\ I_{1} = \frac{5}{500} = \frac{1}{100} A \end{matrix}$

The potential difference across series combination of $R_{3}$ and $R_{4}$

$\Rightarrow V_{2} = (R_{3} + R_{4}) I = 600 \times \frac{1}{100} = 6$ Volt

So, potential difference (across $R_{1}$ )

$V_{1} = 18 - 6 = 12 V$

Current through $R_{1}$ is,

$I = \frac{V_{1}}{R_{1}} = \frac{12}{400} = \frac{3}{100} A$

So current through $R_{2}$ is,

$I_{2} = I - I_{1} = \frac{3}{100} - \frac{1}{100} A = \frac{2}{100} A$

Now, from $V = I R$ , we have,

$R_{2} = \frac{V_{2}}{I_{2}} = \frac{6}{(2 / 100)} = 300 Ω$

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Current Electricity 2 Question 9

9. In the given circuit, the internal resistance of the $18 V$ cell is negligible. If $R_{1} = 400 Ω, R_{3} = 100 Ω$ and $R_{4} = 500 Ω$ and the reading of an ideal voltmeter across $R_{4}$ is $5 V$ , then the value of $R_{2}$ will be

Solution:

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Current Electricity 2 Question 9

9. In the given circuit, the internal resistance of the 18V cell is negligible. If R1=400Ω,R3=100Ω and R4=500Ω and the reading of an ideal voltmeter across R4 is 5V, then the value of R2 will be

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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9. In the given circuit, the internal resistance of the $18 V$ cell is negligible. If $R_{1} = 400 Ω, R_{3} = 100 Ω$ and $R_{4} = 500 Ω$ and the reading of an ideal voltmeter across $R_{4}$ is $5 V$ , then the value of $R_{2}$ will be