SATHEE: Current Electricity 2 Question 4

Current Electricity 2 Question 4

4. For the circuit shown with $R_{1} = 1.0 Ω, R_{2} = 2.0 Ω, E_{1} = 2 V$ and $E_{2} = E_{3} = 4 V$ , the potential difference between the points $a$ and $b$ is approximately (in volt) (2019 Main, 8 April I)

(a) 2.7

(b) 2.3

(d) 3.3

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Solution:

Given circuit is

Above circuit can be viewed as

This is a parallel combination of three cells or in other words, a parallel grouping of three cells with internal resistances.

So, $V_{a b} = E_{e q} = \frac{I_{e q}}{r_{e q}} = \frac{\frac{E_{1}}{r_{1}} + \frac{E_{2}}{r_{2}} + \frac{E_{3}}{r_{3}}}{\frac{1}{r_{1}} + \frac{1}{r_{2}} + \frac{1}{r_{3}}}$

$= \frac{\frac{2}{2} + \frac{4}{2} + \frac{4}{2}}{\frac{1}{2} + \frac{1}{2} + \frac{1}{2}} = \frac{10}{3} V \approx 3.3 V$

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Current Electricity 2 Question 4

4. For the circuit shown with R1=1.0Ω,R2=2.0Ω,E1=2V and E2=E3=4V, the potential difference between the points a and b is approximately (in volt) (2019 Main, 8 April I)

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4. For the circuit shown with $R_{1} = 1.0 Ω, R_{2} = 2.0 Ω, E_{1} = 2 V$ and $E_{2} = E_{3} = 4 V$ , the potential difference between the points $a$ and $b$ is approximately (in volt) (2019 Main, 8 April I)