Current Electricity 2 Question 25

25. Find the emf(V) and internal resistance (r) of a single battery which is equivalent to a parallel combination of two batteries of emfs V1 and V2 and internal resistances r1 and r2 respectively, with polarities as shown in figure

(1997C, 5M)

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Solution:

  1. (a) Equivalent emf (V) of the battery

PD across the terminals of the battery is equal to its emf when current drawn from the battery is zero. In the given circuit,

Current in the internal circuit,

i= Net emf  Total resistance =V1+V2r1+r2

Therefore, potential difference between A and B would be

VAVB=V1ir1VAVB=V1V1+V2r1+r2r1=V1r2V2r1r1+r2

So, the equivalent emf of the battery is

V=V1r2V2r1r1+r2

Note that if V1r2=V2r1:V=0.

If V1r2>V2r1:VAVB= Positive i.e. A side of the equivalent battery will become the positive terminal and vice-versa.

(b) Internal resistance ( r ) of the battery

r1 and r2 are in parallel. Therefore, the internal resistance r will be given by

1/r=1/r1+1/r2 or r=r1r2r1+r2



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