Current Electricity 2 Question 23
23. Two batteries of different emfs and different internal resistances are connected as shown. The voltage across $A B$ in volt is
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Solution:
- $V _{A B}=$ Equivalent emf of two batteries in parallel.
$$ =\frac{E _1 / r _1+E _2 / r _2}{1 / r _1+1 / r _2}=\frac{(6 / 1)+(3 / 2)}{(1 / 1)+(1 / 2)}=5 V $$
