SATHEE: Current Electricity 2 Question 21

Current Electricity 2 Question 21

21. For the resistance network shown in the figure, choose the correct option(s).

(2012)

(a) The current through $P Q$ is zero

(b) $I_{1} = 3 A$

(d) $I_{2} = 2 A$

Integer Answer Type Questions

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Solution:

Due to symmetry on upper side and lower side, points $P$ and $Q$ are at same potentials. Similarly, points $S$ and $T$ are at same potentials. Therefore, the simple circuit can be drawn as shown below

$\begin{aligned} I_{2} & = \frac{12}{2 + 2 + 2} = 2 A \\ I_{3} & = \frac{12}{4 + 4 + 4} = 1 A \\ because I_{1} & = I_{2} + I_{3} = 3 A \\ I_{P Q} & = 0 \\ V_{P} & = V_{Q} \end{aligned}$

Potential drop (from left to right) across each resistance is

$\begin{aligned} \frac{12}{3} & = 4 V \\ ∴ V_{M S} & = 2 \times 4 = 8 V \\ V_{N Q} & = 1 \times 4 = 4 V or V_{S} < V_{Q} \end{aligned}$

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Current Electricity 2 Question 21

21. For the resistance network shown in the figure, choose the correct option(s).

Integer Answer Type Questions

Solution:

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