Current Electricity 2 Question 17

17. In the circuit shown in the figure, the current through

(1998,2M)

(a) the 3Ω resistor is 0.50A

(b) the 3Ω resistor is 0.25A

(c) the 4Ω resistor is 0.50A

(d) the 4Ω resistor is 0.25A

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Solution:

  1. Net resistance of the circuit is 9Ω.

Current drawn from the battery,

i=99=1A= current through 3Ω resistor 

Potential difference between A and B is

VAVB=91(3+2)=4V=8i1i1=0.5Ai2=1i1=0.5A

Similarly, potential difference between C and D

VCVD=(VAVB)i2(2+2)=44i2=44(0.5)=2V=8i3i3=0.25A Therefore, i4=i2i3=0.50.25i4=0.25A



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