Current Electricity 1 Question 9

9. A copper wire is stretched to make it 0.5 longer. The percentage change in its electrical resistance, if its volume remains unchanged is

(2019 Main, 9 Jan I)

(a) 2.0

(b) 1.0

(c) 0.5

(d) 2.5

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Solution:

  1. Electrical resistance of wire of length ’ l ‘, area of cross-section ’ A ’ and resistivity ’ ρ ’ is given as

R=ρlA

Since we know, volume of the wire is

V=A×l

From Eqs. (i) and (ii), we get

R=ol2V

As, the length has been increased to 0.5.

New length of the wire,

l=l+0.5=l+0.005l=1.005l

But V and ρ remains unchanged.

So, new resistance, R=ρ[(1.005)l]2V

Dividing Eq. (iv) and Eq. (iii), we get

RR=(1.005)2

change in the resistance

=RR1×100=[(1.005)21]×100=1.0025



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