SATHEE: Current Electricity 1 Question 3

Current Electricity 1 Question 3

3. In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.

(2019 Main, 10 April I)

One may conclude that

(a) $R (T) = R_{0} e^{- T^{2} / T_{0}^{2}}$

(b) $R (T) = R_{0} e^{T^{2} / T_{0}^{2}}$

(d) $R (T) = \frac{R_{0}}{T^{2}}$

Show Answer

Solution:

From the given graph,

We can say that, $\ln R (T) \propto - \frac{1}{T^{2}}$

Negative sign implies that the slope of the graph is negative.

$\begin{array}{ll} or & \ln R (T) = constant - \frac{1}{T^{2}} \\ \Rightarrow & \ln R (T) = \frac{\exp (const.)}{\exp \frac{1}{T^{2}}} \\ \Rightarrow & \ln R (T) = R_{0} \exp - \frac{T_{0}^{2}}{T^{2}} \end{array}$

Alternate Solution

From graph,

$\frac{\frac{1}{T^{2}}}{\frac{1}{T_{0}^{2}}} + \frac{\ln R (T)}{\ln R (T_{0})} = 1$

$\Rightarrow \ln R (T) = [\ln R (T_{0})] \cdot 1 - \frac{T_{0}^{2}}{T^{2}}$

$R (T) = R_{0} \exp \frac{- T_{0}^{2}}{T^{2}}$

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अगला

Current Electricity 1 Question 3

3. In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.

Solution:

Alternate Solution

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Current Electricity 1 Question 3

3. In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.

Solution:

Alternate Solution

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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