SATHEE: Current Electricity 1 Question 13

Current Electricity 1 Question 13

13. When $5 V$ potential difference is applied across a wire of length $0.1 m$ , the drift speed of electrons is $2.5 \times 10^{- 4} m s^{- 1}$ . If the electron density in the wire is $8 \times 10^{28} m^{- 3}$ the resistivity of the material is close to

(2015 Main)

(a) $1.6 \times 10^{- 8} Ω m$

(b) $1.6 \times 10^{- 7} Ω m$

(d) $1.6 \times 10^{- 6} Ω m$

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Solution:

$i = n e A v_{d}$ or $\frac{V}{R} = n e A v_{d}$

$\begin{aligned} or & \frac{V}{\frac{ρ l}{A}} & = n e A v_{d} \\ ∴ & ρ & = \frac{V}{n e l v_{d}} = resistivity of wire \end{aligned}$

Substituting the given values we have

$\begin{aligned} ρ & = \frac{5}{(8 \times 10^{28)} (1.6 \times 10^{- 19}) (0.1) (2.5 \times 10^{- 4})} \\ \approx 1.6 \times 10^{- 5} Ω - m \end{aligned}$

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Current Electricity 1 Question 13

13. When $5 V$ potential difference is applied across a wire of length $0.1 m$ , the drift speed of electrons is $2.5 \times 10^{- 4} m s^{- 1}$ . If the electron density in the wire is $8 \times 10^{28} m^{- 3}$ the resistivity of the material is close to

Solution:

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Current Electricity 1 Question 13

13. When 5V potential difference is applied across a wire of length 0.1m, the drift speed of electrons is 2.5×10−4ms−1. If the electron density in the wire is 8×1028m−3 the resistivity of the material is close to

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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13. When $5 V$ potential difference is applied across a wire of length $0.1 m$ , the drift speed of electrons is $2.5 \times 10^{- 4} m s^{- 1}$ . If the electron density in the wire is $8 \times 10^{28} m^{- 3}$ the resistivity of the material is close to