Current Electricity 1 Question 10

10. Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If for an n - type semiconductor, the density of electrons is 1019m3 and their mobility is 1.6m2(Vs), then the resistivity of the semiconductor (since, it is an n-type semiconductor contribution of holes is ignored) is close to

(2019 Main, 9 Jan I)

(a) 2Ωm

(b) 0.2Ωm

(c) 0.4Ωm

(d) 4Ωm

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Solution:

  1. Since, it is an n-type semiconductor and concentration of the holes has been ignored. So, its conductivity is given as

σ=neeμe

where, ne is the number density of electron, e is the charge on electron and μe is its mobility.

Substituting the given values, we get

σ=1019×1.6×1019×1.6=2.56

As, resistivity, ρ=1σ=12.56

or

ρ=0.390.4Ωm



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