SATHEE: Centre of Mass 3 Question 16

Centre of Mass 3 Question 16

19. An isolated particle of mass $m$ is moving in horizontal plane $(x - y)$ , along the $X$ -axis, at a certain height above the ground. It suddenly explodes into two fragment of masses $m / 4$ and $3 m / 4$ . An instant later, the smaller fragment is at $y = + 15 c m$ . The larger fragment at this instant is at

(1997 C, 1M)

(a) $y = - 5 c m$

(b) $y = + 20 c m$

(d) $y = - 20 c m$

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Answer:

Correct Answer: 19. (a)

Solution:

Before explosion, particle was moving along $x$ -axis i.e., it has no $y$ -component of velocity. Therefore, the centre of mass will not move in $y$ -direction or we can say $y_{C M} = 0$ .

Now, $y_{C M} = \frac{m_{1} y_{1} + m_{2} y_{2}}{m_{1} + m_{2}}$

Therefore, $0 = \frac{(m / 4) (+ 15) + (3 m / 4) (y)}{(m / 4 + 3 m / 4)}$

$y = - 5 c m$

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Centre of Mass 3 Question 16

19. An isolated particle of mass m is moving in horizontal plane (x−y), along the X-axis, at a certain height above the ground. It suddenly explodes into two fragment of masses m/4 and 3m/4. An instant later, the smaller fragment is at y=+15cm. The larger fragment at this instant is at

Answer:

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