SATHEE: Centre of Mass 2 Question 5

Centre of Mass 2 Question 5

6. A particle moves in the $x - y$ plane under the influence of a force such that its linear momentum is $p (t) = A [\hat{i}$ os $(k t) - \hat{j} \sin (k t)]$ , where, $A$ and $k$ are constants. The angle between the force and the momentum is

(2007, 3M)

(a) $0^{\circ}$

(b) $30^{\circ}$

(d) $90^{\circ}$

Objective Question II (One or more correct option)

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Answer:

Correct Answer: 6. (d)

Solution:

$\begin{aligned} F & = \frac{d p}{d t} = - k A \sin (k t) \hat{i} - k A \cos (k t) \hat{j} \\ p & = A \cos (k t) \hat{i} - A \sin (k t) \hat{j} \end{aligned}$

Since, $F \cdot p = 0$

$∴$ Angle between $F$ and $p$ should be $90^{\circ}$ .

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Centre of Mass 2 Question 5

6. A particle moves in the $x - y$ plane under the influence of a force such that its linear momentum is $p (t) = A [\hat{i}$ os $(k t) - \hat{j} \sin (k t)]$ , where, $A$ and $k$ are constants. The angle between the force and the momentum is

Answer:

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Centre of Mass 2 Question 5

6. A particle moves in the x−y plane under the influence of a force such that its linear momentum is p(t)=A[i^ os (kt)−j^sin⁡(kt)], where, A and k are constants. The angle between the force and the momentum is

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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6. A particle moves in the $x - y$ plane under the influence of a force such that its linear momentum is $p (t) = A [\hat{i}$ os $(k t) - \hat{j} \sin (k t)]$ , where, $A$ and $k$ are constants. The angle between the force and the momentum is