Vectors 5 Question 6

6. A unit vector coplanar with i^+j^+2k^ and i^+2j^+k^ and perpendicular to i^+j^+k^ is

(1992, 2M)

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Answer:

Correct Answer: 6. (53i^,23j^,23k^)

Solution:

  1. Any vector coplanar with i^+j^+2k^ and i^+2j^+k^ is given by

a=x(i^+j^+2k^)+y(i^+2j^+k^)=(x+y)i^+(x+2y)j^+(2x+y)k^

This vector is perpendicular to i^+j^+k^, if

(x+y)1+(x+2y)1+(2x+y)1=04x+4y=0x=y

a=xj^+xk^=x(j^+k^)|a|=2|x|

Hence, the required unit vector is a^=±12(j^+k^)



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