Trigonometrical Ratios and Identities 2 Question 3

3. Suppose sin3xsin3x=m=0nCmcosnx is an identity in x, where C0,C1,,Cn are constants and Cn0. Then, the value of n is… .

(1981, 2M)

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Answer:

Correct Answer: 3. 6

Solution:

  1. Given, sin3xsin3x=m=0nCmcosnx is an identity in x, where, C0,C1,,Cn are constants. sin3xsin3x=143sinxsin3xsin3x

=14322sinxsin3xsin23x

=1432(cos2xcosx)12(1cos6x)=18(cos6x+3cos2x3cosx1)

On comparing both sides, we get n=6



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