Trigonometrical Ratios and Identities 1 Question 23

23. If k=sinπ18sin5π18sin7π18, then the numerical value of k is

(1993,2M)

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Solution:

  1. Using the relation,

sinθsinπ3θsinπ3+θ=sin3θ4

Taking θ=π18, we get

sinπ18sin5π18sin7π18=sinπ64=18

Alternative Method

Given, k=sin10sin50sin70

=cos80cos40cos20

=cosAcos2Acos22A=sin23A23sinA

where, A=20

=sin1608sin20=sin(18020)8sin20=sin208sin20=18



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