Trigonometrical Ratios and Identities 1 Question 22

22. (sin3α)/(cos2α) is

(1992,2M)

Column I Column II
A. positive p. (13π/48,14π/48)
B. negative q. (14π/48,18π/48)
r. (18π/48,23π/48)
s. (0,π/2)

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Solution:

  1. In the interval 13π48,14π48,cos2α<0 and sin3α>0. sin3αcos2α is negative, therefore Bp.

Again, in the interval 18π48,23π48, both sin3α and cos2α are negative, so sin3αcos2α is positive, therefore Ar.



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