Trigonometrical Ratios and Identities 1 Question 1

1. The value of sin10sin30sin50sin70 is

(a) 136

(b) 132

(c) 116

(d) 118

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Answer:

Correct Answer: 1. (c)

Solution:

  1. We have, sin10sin30sin50sin70 =sin(30)[sin(10)sin(50)sin(70)]

=12[sin(10)sin(6010)sin(60+10)]=1214sin(3(10))

[sinθsin(60θ)sin(60+θ)=14sin3θ]

=18sin30=18×12=116



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