Theory of Equations 3 Question 1

1. Let α,β be the roots of the equation, (xa)(xb)=c,c0. Then the roots of the equation (xα)(xβ)+c=0 are

(a) a,c

(b) b,c

(c) a,b

(d) a+c,b+c(1992,2M)

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Solution:

  1. Given, α,β are the roots of (xa)(xb)c=0

(xa)(xb)c=(xα)(xβ)

(xa)(xb)=(xα)(xβ)+c

a,b are the roots of equation (xα)(xβ)+c=0



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