Theory of Equations 1 Question 51

52. Solve for x : (5+26)x23+(526)x23=10(1985,5M)

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Solution:

  1. Given, (5+26)x23+(526)x23=10

Put y=(5+26)x23(526)x23=1y

From Eq. (i), y+1y=10

y210y+1=0y=5±26

(5+26)x23=5+26

or (5+26)x23=526

x23=1 or x23=1

x=±2 or x=±2

x=±2,±2



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