Properties of Triangles 1 Question 15

15. Internal bisector of A of ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and side AB at F. If a,b,c represent sides of ABC, then

(2006,5 M)

(a) AE is HM of b and c

(b) AD=2bcb+ccosA2

(c) EF=4bcb+csinA2

(d) AEF is isosceles

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Answer:

Correct Answer: 15. n=

Solution:

  1. Since, ABC=ABD+ACD

12bcsinA=12cADsinA2+12bADsinA2

Again, AE=ADsecA2=2bcb+c

AE is HM of b and c.

EF=ED+DF=2DE=2ADtanA2=22bcb+ccosA2tanA2=4bcb+csinA2

Since, ADEF and DE=DF and AD is bisector.

AEF is isosceles.

Hence, (a), (b), (c), (d) are correct answers.



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