Probability 3 Question 2

2. Four persons can hit a target correctly with probabilities 12,13,14 and 18 respectively. If all hit at the target independently, then the probability that the target would be hit, is

(2019 Main, 9 April I)

(a) 1192

(b) 2532

(c) 732

(d) 25192

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Answer:

Correct Answer: 2. (b)

1. (d) 2. (b) 3. (b) 4. (a)
5. (c) 6. (d) 7. (a) 8. (a)
9. (d) 10. (c) 11. (c) 12. (b)
13. (b) 14. (a) 15. (a) 16. (b)
17. (a) 18. (c) 19. (b) 20. (b)
21. (a, b) 22. (a,b) 23. (a, d) 24. (b, c)
25. (a, d) 26. (a, d) 27. (a, c) 28. (b, c, d)
29. 14 30. 57 31. 25 32. 3255
33. 19 35. 12 36. 2p2p3 38. 193792

Solution:

  1. Key Idea Use P(A¯)=1P(A) and condition of independent events i.e P(AB)=P(A)P(B)

Given that probability of hitting a target independently by four persons are respectively

P1=12,P2=13,P3=14 and P4=18

Then, the probability of not hitting the target is

=112113114118

=12×23×34×78=732

[ events are independent]

Therefore, the required probability of hitting the target =1( Probability of not hitting the target)

=1732=2532



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