SATHEE: Probability 3 Question 17

Probability 3 Question 17

17. An unbiased die with faces marked $1, 2, 3, 4, 5$ and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 , is

(a) $16 / 81$

(b) $1 / 81$

(c) $80 / 81$

(d) $65 / 81$

(1993, 1M)

Show Answer

Solution:

Let $A =$ getting not less than 2 and not greater than 5

$\Rightarrow A = 2, 3, 4, 5 \Rightarrow P (A) = \frac{4}{6}$

But die is rolled four times, therefore the probability in getting four throws

$= \begin{array}{llll} \frac{4}{6} & \frac{4}{6} & \frac{4}{6} & \frac{4}{6} \end{array} = \frac{16}{81}$

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Probability 3 Question 17

17. An unbiased die with faces marked 1,2,3,4,5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 , is

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17. An unbiased die with faces marked $1, 2, 3, 4, 5$ and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 , is