SATHEE: Probability 2 Question 6

Probability 2 Question 6

6. The probability that at least one of the events $A$ and $B$ occurs is 0.6 . If $A$ and $B$ occur simultaneously with probability 0.2 , then $P (\bar{A}) + P (\bar{B})$ is equal to $(1987, 2 M)$

(a) 0.4

(b) 0.8

(d) 1.4

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Answer:

Correct Answer: 6. $(a, c)$

Solution:

Given, $P (A \cup B) = 0.6, P (A \cap B) = 0.2$

$\begin{aligned} ∴ P (\bar{A}) & + P (\bar{B}) = [1 - P (A)] + [1 - P (B)] \\ = 2 - [P (A) + P (B)] \\ = 2 - [P (A \cup B) + P (A \cap B)] \\ = 2 - [0.6 + 0.2] = 1.2 \end{aligned}$

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Probability 2 Question 6

6. The probability that at least one of the events $A$ and $B$ occurs is 0.6 . If $A$ and $B$ occur simultaneously with probability 0.2 , then $P (\bar{A}) + P (\bar{B})$ is equal to $(1987, 2 M)$

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Probability 2 Question 6

6. The probability that at least one of the events A and B occurs is 0.6 . If A and B occur simultaneously with probability 0.2 , then P(A¯)+P(B¯) is equal to (1987,2M)

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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6. The probability that at least one of the events $A$ and $B$ occurs is 0.6 . If $A$ and $B$ occur simultaneously with probability 0.2 , then $P (\bar{A}) + P (\bar{B})$ is equal to $(1987, 2 M)$