Probability 1 Question 21

29. Six boys and six girls sit in a row at random. Find the probability that

(i) the six girls sit together.

(ii) the boys and girls sit alternatively.

(1978, 3M)

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Answer:

Correct Answer: 29. (i) 1132 (ii) 1462

Solution:

  1. (i) The total number of arrangements of six boys and six girls =12 !

Required probability =6!×7!(12)!=1132

[since, we consider six girls at one person]

(ii) Required probability =2×6!×6!(12)!=1462



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