Permutations and Combinations 3 Question 5

5. Consider a class of 5 girls and 7 boys. The number of different teams consisting of 2 girls and 3 boys that can be formed from this class, if there are two specific boys A and B, who refuse to be the members of the same team, is

(2019 Main, 9 Jan I)

(a) 350

(b) 500

(c) 200

(d) 300

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Answer:

Correct Answer: 5. (d)

Solution:

  1. Number of girls in the class =5 and number of boys in the class =7

Now, total ways of forming a team of 3 boys and 2 girls

=7C35C2=350

But, if two specific boys are in team, then number of ways =5C15C2=50

Required ways, i.e. the ways in which two specific boys are not in the same team =35050=300.

Alternate Method

Number of ways when A is selected and B is not

=5C25C2=100

Number of ways when B is selected and A is not

=5C25C2=100

Number of ways when both A and B are not selected

=5C35C2=100

Required ways =100+100+100=300.



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