Permutations and Combinations 3 Question 1

1. The number of 6 digits numbers that can be formed using the digits 0,1,2,5,7 and 9 which are divisible by 11 and no digit is repeated, is

(2019 Main, 10 April I)

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Answer:

Correct Answer: 1. (a)

Solution:

  1. Key Idea Use divisibility test of 11 and consider different situation according to given condition.

Since, the sum of given digits

0+1+2+5+7+9=24

Let the six-digit number be abcdef and to be divisible by 11 , so the difference of sum of odd placed digits and sum of even placed digits should be either 0 or a multiple of 11 means |(a+c+e)(b+d+f)| should be either 0 or a multiple of 11 .

Hence, possible case is a+c+e=12=b+d+f (only) Now, Case I

set a,c,e=0,5,7 and setb,d,f=1,2,9

So, number of 6 -digits numbers =(2×2!)×(3!)=24

[a can be selected in ways only either 5 or 7].

Case II

Set a,c,e=1,2,9 and set b,d,f=0,5,7

So, number of 6 -digits numbers =3!×3!=36

So, total number of 6 -digits numbers =24+36=60



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