Parabola 2 Question 25

4. The equation of a tangent to the parabola, $x^{2}=8 y$, which makes an angle $\theta$ with the positive direction of $X$-axis, is

(2019 Main, 12 Jan, II)

(a) $y=x \tan \theta-2 \cot \theta$

(b) $x=y \cot \theta+2 \tan \theta$

(c) $y=x \tan \theta+2 \cot \theta$

(d) $x=y \cot \theta-2 \tan \theta$

Show Answer

Answer:

Correct Answer: 4. (b)

Solution:

  1. Given parabola is $x^{2}=8 y$

Now, slope of tangent at any point $(x, y)$ on the parabola (i) is

$$ \frac{d y}{d x}=\frac{x}{4}=\tan \theta $$

$[\because$ tangent is making an angle $\theta$ with the positive direction of $X$-axis]

$$ \text { So, } x=4 \tan \theta $$

$$ \begin{aligned} & \Rightarrow \quad 8 y=(4 \tan \theta)^{2} \\ & \Rightarrow \quad y=2 \tan ^{2} \theta \quad \text { [on putting } x=4 \tan \theta \text { in Eq. (i)] } \end{aligned} $$

Now, equation of required tangent is

$y-2 \tan ^{2} \theta=\tan \theta(x-4 \tan \theta)$

$\Rightarrow y=x \tan \theta-2 \tan ^{2} \theta \Rightarrow x=y \cot \theta+2 \tan \theta$



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक