SATHEE: Matrices and Determinants 4 Question 5

Matrices and Determinants 4 Question 5

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5. If the system of linear equations $x - 2 y + k z = 1, 2 x + y + z = 2, 3 x - y - k z = 3$ has a solution $(x, y, z), z \neq 0$ , then $(x, y)$ lies on the straight line whose equation is (2019 Main, 8 April II)

======= ####5. If the system of linear equations $x - 2 y + k z = 1, 2 x + y + z = 2, 3 x - y - k z = 3$ has a solution $(x, y, z), z \neq 0$ , then $(x, y)$ lies on the straight line whose equation is

(2019 Main, 8 April II)

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(a) $3 x - 4 y - 4 = 0$

(b) $3 x - 4 y - 1 = 0$

(d) $4 x - 3 y - 1 = 0$

Show Answer

Answer:

Correct Answer: 5. (c)

Solution:

Given system of linear equations

$\begin{array}{r} x - 2 y + k z = 1 \\ 2 x + y + z = 2 \\ and 3 x - y - k z = 3 \end{array}$

has a solution $(x, y, z), z \neq 0$ .

On adding Eqs. (i) and (iii), we get

$\begin{aligned} x - 2 y + k z + 3 x - y - k z & = 1 + 3 \\ 4 x - 3 y & = 4 \\ 4 x - 3 y - 4 & = 0 \end{aligned}$

This is the required equation of the straight line in which point $(x, y)$ lies.

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Matrices and Determinants 4 Question 5

5. If the system of linear equations $x - 2 y + k z = 1, 2 x + y + z = 2, 3 x - y - k z = 3$ has a solution $(x, y, z), z \neq 0$ , then $(x, y)$ lies on the straight line whose equation is (2019 Main, 8 April II)

Answer:

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Matrices and Determinants 4 Question 5

5. If the system of linear equations x−2y+kz=1,2x+y+z=2,3x−y−kz=3 has a solution (x,y,z),z≠0, then (x,y) lies on the straight line whose equation is (2019 Main, 8 April II)

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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5. If the system of linear equations $x - 2 y + k z = 1, 2 x + y + z = 2, 3 x - y - k z = 3$ has a solution $(x, y, z), z \neq 0$ , then $(x, y)$ lies on the straight line whose equation is (2019 Main, 8 April II)