Matrices and Determinants 4 Question 19
20. The number of values of $k$ for which the system of equations $(k+1) x+8 y=4 k$ and $k x+(k+3) y=3 k-1$ has infinitely many solutions, is/are
(2002, 1M)
(a) 0
(b) 1
(c) 2
(d) $\infty$
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Answer:
Correct Answer: 20. (b)
Solution:
- For infinitely many solutions, we must have
$$ \frac{k+1}{k}=\frac{8}{k+3}=\frac{4 k}{3 k-1} \Rightarrow k=1 $$
